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2x^2+7x=220
We move all terms to the left:
2x^2+7x-(220)=0
a = 2; b = 7; c = -220;
Δ = b2-4ac
Δ = 72-4·2·(-220)
Δ = 1809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1809}=\sqrt{9*201}=\sqrt{9}*\sqrt{201}=3\sqrt{201}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-3\sqrt{201}}{2*2}=\frac{-7-3\sqrt{201}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+3\sqrt{201}}{2*2}=\frac{-7+3\sqrt{201}}{4} $
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